def generate_index(directory, indent=0): result = "" for name in sorted(os.listdir(directory)): path = os.path.join(directory, name) if os.path.isdir(path) and name.lower() != "unsorted": result += " " * indent + f"<li>{name}/<ul>\n" result += generate_index(path, indent + 1) result += " " * indent + "</ul></li>\n" elif name.endswith(".mkv"): result += " " * indent + f"<li>{name}</li>\n" return result
import os
Movies/ ├── Action/ │ ├── 2020/ │ │ └── ExampleMovie1080p.mkv │ └── 2021/ │ └── NewAction1080p.mkv ├── Comedy/ │ └── 2019/ │ └── FunnyComedy1080p.mkv Use naming conventions (e.g., YYYY-MM-DD for dates or Title-S01E01 for TV shows). A script to generate an HTML index of parent directories: index of parent directory 1080p mkv
html = f"<ol>\n{generate_index('Movies/')}\n</ol>" with open("index.html", "w") as f: f.write(html) For a parent directory, this index could help
Next, I should think about the technical aspects. An index file might be an HTML, JSON, or XML file that lists directories and files. For a parent directory, this index could help applications or users navigate without manually exploring each folder. The 1080p MKV files are media files, so the index might include metadata like titles, genres, or release years to help categorize them. So, I should focus on explaining how to
Another angle is if the user encountered an error or problem with the index not working correctly, but the query doesn't specify that. So, I should focus on explaining how to create and use such an index, perhaps with examples in different programming languages.
I should also consider if the user wants to parse an existing index or create one from scratch. Maybe they need help writing a script to traverse directories and generate a list of all 1080p MKV files, complete with their parent directories.